# Table 5 Different probabilities expressed by the prediction model

Probability f(Y)  0.29
Ranges Expression Landslide occurrence
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)};{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\le}\mathbf{0.229}$$ Exp(−(−17.34 + 20.31))/1 +  exp (−(−17.34 + 20.31)) 4.88%
$$\mathbf{0.229}<{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)},{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\le}\mathbf{0.394}$$ Exp(−(−17.34 − 0.0000000013 + 0.0000000002))/(1 +  exp (−(−17.34 − 0.0000000013 + 0.0000000002))) 99.99%
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)},{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\ge}\mathbf{0.394}$$ Exp(−(−17.34 + 0.0000000003 − 0.000000002))/(1 +  exp (−(−17.34 + 0.0000000003 − 0.000000002))) 99.99%
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)}\boldsymbol{\le}\mathbf{0.229}$$,
$$\mathbf{0.229}<{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\le}\mathbf{0.394}$$
Exp(−(−17.34 + 20.31 + 0.0000000002))/(1 +  exp (−(−17.34 + 20.31 + 0.0000000002))) 4.88%
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)}\boldsymbol{\le}\mathbf{0.229}$$,
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}>\mathbf{0.394}$$
Exp(−(−17.34 + 20.31 − 0.000000002))/(1 +  exp (−(−17.34 + 20.31 − 0.000000002))) 4.88%
$$\mathbf{0.229}<{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)}\boldsymbol{\le}\mathbf{0.394}$$,
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\le}\mathbf{0.229}$$
Exp(−(−17.34 + 0.0000000013))/(1 +  +  exp (−(−17.34 + 0.0000000013))) 99.99%
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\le}\mathbf{0.229}$$,
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)}>\mathbf{0.394}$$
Exp(−(−17.338 + 0.0000000002))/(1 +  exp (−(−17.338 + 0.0000000002))) 99.99%
$$\mathbf{0.229}<{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)}\boldsymbol{\le}\mathbf{0.394}$$,
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}>\mathbf{0.394}$$
Exp(−(−17.34 − 0.0000000013 + 0.000000002))/(1 +  exp (−(−17.34 − 0.0000000013 + 0.000000002))) 99.99%
$$\mathbf{0.229}<{\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{2}}\right)}\boldsymbol{\le}\mathbf{0.394}$$,
$${\boldsymbol{f}}_{\left({\boldsymbol{X}}_{\mathbf{1}}\right)}>\mathbf{0.394}$$
Exp(−(−17.34 + 0.0000000002 + 0.00000000035))/(1 +  exp (−(−17.34 + 0.0000000002 + 0.00000000035))) 99.99%